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From: Stewart on 28 Aug 2009 07:14 Yesterday my opponent's drive put his ball in a plug (totally unplayable) on the green side of a water hazard. I thought he could declare it unplayable and drop on the tee side of the hazard at a cost of one stroke. He though he still had to drop the ball in the hazard (no water at present) but still count additional stroke. If he dropped as I suugested then he thought that was adding 2 strokes; one drop into the hazard and one drop on the tee side. Who was right? Thank you.
From: sugnaboris on 28 Aug 2009 09:13 On 28 Aug, 12:14, "Stewart" <h...(a)invalid.supanet.co.uk> wrote: > Yesterday my opponent's drive put his ball in a plug (totally unplayable) on > the green side of a water hazard. > I thought he could declare it unplayable and drop on the tee side of the > hazard at a cost of one stroke. > He though he still had to drop the ball in the hazard (no water at present) > but still count additional stroke. If he dropped as I suugested then he > thought that was adding 2 strokes; one drop into the hazard and one drop on > the tee side. > Who was right? > Thank you. Neither of you.
From: Mark Myers on 28 Aug 2009 10:40 On Fri, 28 Aug 2009 06:13:30 -0700 (PDT), sugnaboris said... > On 28 Aug, 12:14, "Stewart" <h...(a)invalid.supanet.co.uk> wrote: > > Yesterday my opponent's drive put his ball in a plug (totally unplayable) on > > the green side of a water hazard. > > I thought he could declare it unplayable and drop on the tee side of the > > hazard at a cost of one stroke. > > He though he still had to drop the ball in the hazard (no water at present) > > but still count additional stroke. If he dropped as I suugested then he > > thought that was adding 2 strokes; one drop into the hazard and one drop on > > the tee side. > > Who was right? > > Thank you. > > Neither of you. Indeed. You can't declare the ball unplayable in a water hazard. You either play it, or pick it up (if you can) and proceed under the rules for a water hazard. That is close to what you said, but not quite the same. For one thing, when dropping, you have to pay attention to where the ball crossed the line of the hazard, it's not as simple as 'the tee side of the hazard'. Picking up and dropping outside the hazard, in one of the correct dropping spots, comes with a penalty of one stroke. -- Mark Myers usenet at mcm2007 dot plus dot com I call that a radical interpretation of the text.
From: Stewart on 28 Aug 2009 14:22 Thank you; as you will suspect our games is just a friendly but we like to try and keep to the rules. I appreciate that the hazard still has to be in the same line to the hole but I think you can drop the ball as far back (on the tee side) as you wish. "Mark Myers" <nospam(a)see.sig> wrote in message news:MPG.2501fcaf7aaabb01989803(a)news.altopia.net... On Fri, 28 Aug 2009 06:13:30 -0700 (PDT), sugnaboris said... > On 28 Aug, 12:14, "Stewart" <h...(a)invalid.supanet.co.uk> wrote: > > Yesterday my opponent's drive put his ball in a plug (totally > > unplayable) on > > the green side of a water hazard. > > I thought he could declare it unplayable and drop on the tee side of the > > hazard at a cost of one stroke. > > He though he still had to drop the ball in the hazard (no water at > > present) > > but still count additional stroke. If he dropped as I suugested then he > > thought that was adding 2 strokes; one drop into the hazard and one drop > > on > > the tee side. > > Who was right? > > Thank you. > > Neither of you. Indeed. You can't declare the ball unplayable in a water hazard. You either play it, or pick it up (if you can) and proceed under the rules for a water hazard. That is close to what you said, but not quite the same. For one thing, when dropping, you have to pay attention to where the ball crossed the line of the hazard, it's not as simple as 'the tee side of the hazard'. Picking up and dropping outside the hazard, in one of the correct dropping spots, comes with a penalty of one stroke. -- Mark Myers usenet at mcm2007 dot plus dot com I call that a radical interpretation of the text.
From: david s-a on 28 Aug 2009 18:59
Stewart wrote: > Yesterday my opponent's drive put his ball in a plug (totally unplayable) on > the green side of a water hazard. > I thought he could declare it unplayable and drop on the tee side of the > hazard at a cost of one stroke. > He though he still had to drop the ball in the hazard (no water at present) > but still count additional stroke. If he dropped as I suugested then he > thought that was adding 2 strokes; one drop into the hazard and one drop on > the tee side. > Who was right? > Thank you. > > If it is an ordinary water hazard (yellow stakes) there are just three options. 1) Play the ball as it lies, in the hazard, without grounding the club........NO PENALTY 2) Rule 26-1a.... "Play a ball as nearly as possible at the spot from which the original ball was last played".......ONE STROKE PENALTY. 3) Rule 26-1b....."Drop a ball behind the water hazard, keeping the point at which the original ball last crossed the margin of the hazard directly between the hole and the spot on which the ball is dropped, with no limit to how far beind the water hazard the ball is dropped...."....ONE STROKE PENALTY. For newbies, and others not familiar with the terminology, the phrase "drop the ball behind the water hazard" is not as clear as it could be. What it means is that no matter where the ball last crossed the margin of the water hazard the option 3) above generally intends that the next stroke be played across the water hazard, along the line of play indicated. cheers david |